(v^2-3v+4)(5v-2)=0

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Solution for (v^2-3v+4)(5v-2)=0 equation: 


Simplifying
(v2 + -3v + 4)(5v + -2) = 0

Reorder the terms:
(4 + -3v + v2)(5v + -2) = 0

Reorder the terms:
(4 + -3v + v2)(-2 + 5v) = 0

Multiply (4 + -3v + v2) * (-2 + 5v)
(4(-2 + 5v) + -3v * (-2 + 5v) + v2(-2 + 5v)) = 0
((-2 * 4 + 5v * 4) + -3v * (-2 + 5v) + v2(-2 + 5v)) = 0
((-8 + 20v) + -3v * (-2 + 5v) + v2(-2 + 5v)) = 0
(-8 + 20v + (-2 * -3v + 5v * -3v) + v2(-2 + 5v)) = 0
(-8 + 20v + (6v + -15v2) + v2(-2 + 5v)) = 0
(-8 + 20v + 6v + -15v2 + (-2 * v2 + 5v * v2)) = 0
(-8 + 20v + 6v + -15v2 + (-2v2 + 5v3)) = 0

Combine like terms: 20v + 6v = 26v
(-8 + 26v + -15v2 + -2v2 + 5v3) = 0

Combine like terms: -15v2 + -2v2 = -17v2
(-8 + 26v + -17v2 + 5v3) = 0

Solving
-8 + 26v + -17v2 + 5v3 = 0

Solving for variable 'v'.

The solution to this equation could not be determined.

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